Advantages of Optic Fibers

1. Optical fibers have greater information carrying capacities than metallic conductors.

2. Fibers and fiber cables are very strong and flexible. So fibres are so slender that they do not break when wrapped around.

3. One of the most important advantages of fibers is that they can carry large amount of information in either digital or analog form.

4. An optical fiber is well protected from external interference and coupling with other communication channels. It is because an optic fiber made of  either glass or plastic is an insulator.

5. Electromagnetic interference caused by lightning and sparking etc doesn't effect fibers.

6. As compared to Copper, corrosion due to water or chemicals is less for glass. Glass fiber themselves can withstand high temperature before deteriorating. 

7. Fiber offers a degree of security and privacy. Because fibers do not radiate energy with in them, it is difficult for an intruder to detect signal being transmitted.

How does an image change in a 3D hologram depending on angle of viewing?

 A Hologram is made by taking a single coherent beam, usually from a LASER, and splitting it into two beams.

One of the beams called a reference beam, directly hits a photographic plate where as other is reflected off an object (whose image needs to be stored in the Hologram). The interference pattern of these two beams is stored as Hologram.

When light is focussed on this Holographic plate, it reflects off the plate, but after mixing with the stored pattern.

 So if the original light beam that was used is directed at the corrected angle, it cancels out the component corresponding to reference beam and we see the object.

However, in a typical room, Light hits hologram from all angles and is also reflected back in all angles. Hence, there will be a beam that will fall on plate at same angle as that of reference and reflect the image of the object. If our eye happens to be in the path of the reflected beam then we can see the stored object.

If two interference patterns were stored simultaneously with different reference beam, we can see two different images depending on the angle of viewing. Because the light reaches each eye is not exactly the same, the 3D effect or perception of depth is produced.

ALL ABOUT NUCLEAR CROSSSECTION

The probability of a Nuclear Reaction can be defined in terms of number of particles emitted or number of nuclei undergoing transmutation for a specified number of incident particles.

It is usually expressed in terms of an effective area presented by a Nucleus towards the beam of bombarding particles, such that the number of incident particles that would strike such an area, calculated upon a purely geometrical basis, is the number observed to lead to Nuclear Reaction given in question.

This effective area is called crosssection for that reaction.

Thus the probability of occurrence of a particular Nuclear Reaction is described by effective crosssection for that process.

The crosssection may also be defined as 

1) The probability that an event may occur when a single nucleus is exposed to a beam of  particles of total flux one particle per unit area.

2) The probability that an event may occur when a single particle is shot perpendicularly at a target consisting of one particle per unit area.

The idea of crosssection gives imaginary area associated with each nucleus, the area is so chosen that if bombarded  particle passes through it the reaction takes place, otherwise it is not.

The total nuclear crosssection is effective area possessed by a nucleus for removing incident particles from a collimated beam by all possible process.

This can be written as sum of several partial crosssections which represent contributions to various distinct, independent processes which can remove particles  from incident beam.

Thus,

𝛔t  = 𝛔s  + 𝛔r                                                    ---------------(1)

𝛔t  is "Total crosssection"

𝛔s is "Scattering crosssection"

𝛔r is "Reaction Crossection"


Scattering Crossection

Scattering crosssection can be classified as 

i) Inelastic scattering

ii) Elastic Scattering

Thus, we get

𝛔s  = 𝛔el  + 𝛔inel                                                          --------(2)

These partial crossections can still be subdivided.

In case of elastic scattering separate partial crosssections cannot be written because of possibility of interference between them.

On other hand all inelastic scattering processses are incoherent and their crosssections are additive.  

𝛔inel  = 𝛔1  + 𝛔2 + 𝛔3 + .........                                      ------(3)

Differential crosssection

The distribution in angle of emitted particles in a nuclear reaction can be described in terms of a crosssection which is a function of angular coordinates in problem.

The crosssection which defines a distribution of emitted particles with respect to solid angle is called differential crosssection. It is defined by  d𝛔/d.

Partial crosssection for a given process is

𝛔  = ∫(d𝛔/dΩ)*dΩ                                                                ------(4)

Expression of crosssection for a Nuclear Reaction


Consider a mono energetic beam of particles incident on a target shown in Fig.

Let the beam be uniform and contain ‘n’ particles per unit volume moving with a velocity ‘V’ with respective to stationary target.

Clearly the product ‘nV’ gives number of particles crossing a unit area perpendicular to beam per unit time. It defines flux ‘F’ of particles in incident beam.

                                            F = nV -------------------------------(1)

It is customary to normalize number of particles to one particle per volume ‘V’.

                                            n = 1/V ------------------------------(2)

The detector detects all particles scattered through an angle ‘𝛳' into solid angle d.

The number of particles dN detected per unit time depends on following factors:

i)                    Flux of incident beam, F

ii)                   The solid angle, d

iii)                 Number of independent scattering centers in target that are intercepted by the beam. Let these be N.

                                   dN = 𝛔(𝛳)*F*dΩ*N ---------------------(3)

𝛔(𝛳) is constant of proportionality defines differential scattering crosssection.

We can put

                                   𝛔(𝛳)*dΩ =d𝛔(𝛳) 

                       𝛔(𝛳) =d𝛔(𝛳) / d -----------------------(4)

  The total number of particles scattered per unit time is obtained by integrating over  entire solid angle.

                                       N = F*N*𝛔total  --------------------------(5)

where,

    Total Crosssection  𝛔total  = ∫𝛔(𝛳) d ---------------------(6)

 𝛔total has dimensions of area.

Unit used to express crosssections is barn.

1 barn = 10⁻²⁸ cm².


The area 'a' intercepted by beam contains 'N' scattering centers. Total number of incident particles per unit time is given by

Nincident = F*a, where 'a' is area intercepted by beam; 'F' is incident flux.

Total number of scattered particles per unit time is

NscatteredF*N*𝛔total

(Nscattered/Nincident) = (N*𝛔total)/a   ------------------------(7)

𝛔total is equal to area effective in scattering for one scattering center.

What is Penetration depth in Super Conductors

 In 1935, F. London and H. London described Meissner effect and zero resistivity by adding two conditions E=0(absence of Resistivity) and B=0(Meissner effect) to Maxwells Electromagnetic equations.

According to them, the applied field does not suddenly drop to zero at the surface of super conductor, but decays exponentially according to equation

B(x) = Bₐexp(-x/ƛ)

B(x) - Magnetic field at depth 'x' of material

 Bₐ  - Applied field; ƛ - penetration depth

Penetration depth is the length or depth from surface of metal at which the magentic field falls to 1/e of its original value.

Generally the magnetic field is likely to penetrate a superconductor to a depth of 10 - 100 nm.

Penetration depth doesn't have a fixed value but varies with temperature.

ƛ = ƛ / [1-(T/Tc)⁴]




ALPHA PARTICLE SPECTRUM? - DETAILED EXPLANATION

We have discussed that every alpha(𝛼) emitter has only one associated 𝛼 energy. This is experimentally true for many 𝛼 emitter where one finds that velocity spectrum of alpha particle from these isotopes is always a shar line spectrum. This is to be expected that since the emission of an alpha particle is a result of energy transition between two different nuclear states.

in 1930, S. Rosenblum, in France proved by means of spectograph that the 𝛼 particles from Thc(Bi²¹²), all of which had been thought to have same energy, actually were consisted of number of groups of particles with slightly different energies. The 𝛼 particles form a given radioactive substance were collimated with slits and after deflection thru 180⁰ with strong magnetic field, formed lines on photographic plate.

For example, ₈₄Po²¹⁴ decays to ₈₂Pb²¹⁰ byemitting 4 groups of  𝛼 particles having ranges in air 6.91cm, 7.79 cm, 9.04cm and 11.51cm. These ranges correspond to energies 7.68MeV, 8.28MeV, 9.07MeV & 10.51 MeV respectively.

Another example is decay of ₉₀Th²²⁸. 

₉₀Th²²⁸     →    ₈₈Ra²²⁴ + 𝛼

It comprises of five groups of 𝛼-particles with different energies.




𝛼-particle which is emitted by transformation of excited state of parent nucleus to ground state of daughter nucleus will have maximum energy.

In the above example, out of 5, four groups of  𝛼-particles leave the daughter nuclei in excited state. The fifth group of 5.42MeV 𝛼-rays take one to ground state of daughter nuclei. We can note from figure that excited states of nuclei reach ground state by emitting 𝜸-rays shown by vertical wavy lines.

Thus the fine structure of 𝛼-spectrum tells us about energy levels in daughter nuclei. We emphasize that existence of these different 𝛼-energy groups and 𝜸-rays proves the existence of nuclear energy levels.

Long Range 𝛼-particles:

If the parent 𝛼-emitter emits 𝛼-particles when it is in an excited state, then we get long range 𝛼-particles.  This is because the energy of excitation becomes available to 𝛼-particles as they reach the ground state of daughter nuclei.

The following figure illustrates the emission of long range 𝛼-particles from ₈₄Po²¹⁴.



𝛼ₒ - normal 𝛼-group corresponding to transition between ground states of  ²¹²Po and ²⁰⁸Pb.

𝛼₁, 𝛼₂ - these groups originate from transitions from excited states of parent ²¹²Po to daughter ²⁰⁸Pb directly.

Thus, nuclear spectroscopic studies of long range 𝛼-emitters provide information about nuclear energy levels of parent.